6g^2+23g+7=0

Solution for 6g^2+23g+7=0 equation:

6g^2+23g+7=0

a = 6; b = 23; c = +7;
Δ = b2-4ac
Δ = 232-4·6·7
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-19}{2*6}=\frac{-42}{12}
=-3+1/2
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+19}{2*6}=\frac{-4}{12}
=-1/3
$